Algebra 2

See:

https://web2.0calc.com/questions/amount-of-real-solutions

2. What are the real solutions to the system of equations? 

Y= X^2 - 5x+ 6 

Y= -4x+6

Set the y's qual and we have

x^2 - 5x + 6 = -4x + 6      simplify

x^2 - x = 0  factor

x ( x - 1 ) = 0

Setting both factors to 0 and solving for x produces

x = 0     or   x  = 1

So....the solutions are  ( 0, 6)  and ( 1, 2)

3. This system has one solution

y= 8x-14

Y=x^2+4x-10 

what is the Y coordinate of the solution? 

x^2 + 4x - 10 =  8x - 14

x^2 - 4x + 4 = 0

(x - 2) ^2 = 0

x = 2

And y =  8(2) - 14  =   2