Given that \(6^{x+y} = 36\) and \(6^{x+5y}=216\), what is x?
what is x?
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\(6^{x+y} = 36\\ 6^{x+y}=6^2\\ 6^{x+5y}=216\\ 6^{x+5y}=6^3\\ x+y=2\\ y=2-x\)
\(x+5y=3\\ x=3-5y\\ x=3-5(2-x)\\ x=3-10+5x\\ -4x=-7\\ \color{blue}x=1.75 \)
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