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-x2+4x=5 

Solved by quadratic formula 

 Sep 18, 2020
 #1
avatar+27709 
+1

\(x = {-b \pm \sqrt{b^2-4ac} \over 2a}\)  

 

 

-x^2 + 4x -5 = 0          a = -1   b = 4   c = -5     plug in to the formula above to find the two values of x       

 Sep 18, 2020

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