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Determine the horizontal asymptote for r(x) =x^3 - 2x^2 + 3/x - 2, if one exists.

 

A)There is no horizontal asymptote.

B)The horizontal asymptote is y = 0.

C)The horizontal asymptote is x = 2.

D)The horizontal asymptote is y = x - 1.

 

 

 Simplify.
 

x^2 + 5x - 14

__________

x^2 + 8x + 7

 

 

A) 7x/x

B) x - 2/x + 1

C) x - 2/x + 7

D) x + 7/x + 1

 Aug 16, 2017
 #1
avatar+98197 
+1

 

[x ^3 - 2x^2 + 3  ] / [ x -2 ]

 

Because the polynomial in the  numerator is of a greater degree than the polynomial in the denominator, there is no horizontal asymptote

 

 

x^2 + 5x - 14                                  [ ( x + 7) (x - 2) ]                         [ x - 2 ]

__________        factors as           _____________      =                ______    

x^2 + 8x + 7                                   [ (x + 7) ( x + 1) ]                        [ x + 1 ]    

 

 

 

 

 

cool cool cool         

 Aug 16, 2017

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