Find the set of values \(a\) for which the range of the function

\(f(x) = \frac{x^2 + a}{x + 1}\)

is the set of all real numbers.

Enter you answer in interval notation.

EW....I get that the function will have a range of all real numbers when a is in the interval ( -infinity, -1 ]

oh ok, is there an explanation to why?

oof, the answer is (-infinity, -1), but now i understand why. Thanks for the help anyway!!!