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Find the set of values \(a\) for which the range of the function

 

\(f(x) = \frac{x^2 + a}{x + 1}\)


is the set of all real numbers. 

 

Enter you answer in interval notation.

 Jan 15, 2020
edited by EpicWater  Jan 15, 2020
 #1
avatar+109739 
+1

EW....I get that  the function will have a range of all real numbers when  a is in the interval  ( -infinity, -1  ]

 

cool cool cool

 Jan 16, 2020
 #2
avatar+287 
+1

oh ok, is there an explanation to why?

 Jan 16, 2020
 #3
avatar+287 
+1

oof, the answer is (-infinity, -1), but now i understand why. Thanks for the help anyway!!!

 Jan 16, 2020

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