+0  
 
0
261
1
avatar

fine the equation of a line that passes through (-7, -6) and (3, -6)

Guest Aug 24, 2017

Best Answer 

 #1
avatar+7155 
+3

First let's find the slope.

 

slope  =  \(\frac{\text{difference of y values}}{\text{difference of x values}}=\frac{-6--6}{-7-3}=\frac{0}{-10}=0\)

 

So, in point-slope form, using the point  (-7, -6) ,  the equation is....

 

y - -6  =  0(x - -7)

 

y + 6  =  0

 

y  =  -6

 

And..we could have noticed from the beginning that the  y  value of both points is  -6  . That means it must be a horizontal line at  y = -6  .  smiley

hectictar  Aug 25, 2017
 #1
avatar+7155 
+3
Best Answer

First let's find the slope.

 

slope  =  \(\frac{\text{difference of y values}}{\text{difference of x values}}=\frac{-6--6}{-7-3}=\frac{0}{-10}=0\)

 

So, in point-slope form, using the point  (-7, -6) ,  the equation is....

 

y - -6  =  0(x - -7)

 

y + 6  =  0

 

y  =  -6

 

And..we could have noticed from the beginning that the  y  value of both points is  -6  . That means it must be a horizontal line at  y = -6  .  smiley

hectictar  Aug 25, 2017

8 Online Users

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.