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Find the number of positive integers n so that 4 < sqrt(n) < 10

 Apr 1, 2023
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First, we square both sides of the inequality to get rid of the square root sign:

$4 < \sqrt{n} < 10$

$16 < n < 100$

So, we need to count the number of integers between 16 and 100, excluding 16 and 100 themselves. To do this, we subtract 1 from the count of integers between 1 and 100 and then subtract 1 again for the excluded upper bound:

$99 - 1 - 1 = 97$

Therefore, there are 97 positive integers n that satisfy the inequality $4 < \sqrt{n} < 10$.

 Apr 1, 2023

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