write an equation in slope-intercept form for the line that satisfies the following condition. passes through (10,16), perpindicular to the graph of 9x+12y=15

Guest Sep 11, 2017

#1**+1 **

We need to find the slope of 9x+12y=15

In this form, Ax + By = C....the slope is given by -A / B = -9 / 12 = -3 / 4

And a line perpendicular to this will have a negative reciprocal slope = 4 / 3

So.....the equation of a line with this slope passing through (10, 16) is given by :

y = (4/3) ( x - 10) + 16 simplify

y = (4/3)x - 40/3 + 16

y = (4/3)x - 40/3 + 48/3

y = (4/3)x + 8/3 and this is in slope-intercept form

CPhill
Sep 11, 2017