Help?!?!
Find the value of x so that the three given terms are consecutive terms of an arithmetic sequence.
2x – 1, 4x, and 5x + 3
+128408 2x - 1 is the first term
And we have that the first term + d = the second term
2x - 1 + d = 4x → d = 2x + 1 (1)
And the first term + 2d = the third term
2x - 1 + 2d = 5x + 3 → 2d = 3x + 4 (2)
Sub (1) into (2) and we have that
2 [2x + 1] = 3x + 4
4x + 2 = 3x + 4 subtract 3x, 2 from both sides
x = 2 and using (1) → d = 2(2) + 1 = 5
So
The first term is 2(2) - 1 = 3
The second term is 4(2) = 8
And the third term is 5(2) + 3 = 13
Note that the difference between terms = d = 5
