A rectangle measures has a width of 12 inches and a length of 19 inches. If the length and the width are increased the same amount, the new area is six more than three times the original area. What is the width of the new rectangle?
electric pav, if you go help with the (xyz-1)(2xyz + x + y + z + 2) = 2021(x+y+z-2) question, I can take over answering this one. let the increase be x. then, (x+12)(x+19) = 690. Then, bash gives x=11. add to the width and you get 23.
12 * 19 = 228 in2
(12 +x ) * (19+x) = 3 * 228 + 6
x^2 +31x + 228 = 690
x ^2 + 31x - 462 = 0 Quadratic formula shows x = 11 in new width = 12 + 11 = 23 inches
ele pav, plz help with (xyz-1)(2xyz + x + y + z + 2) = 2021(x+y+z-2)question. thx