Suppose that \(a^2\) varies inversely with \(b^3\). If \(a=7\)when \(b=3\), find the value of \(a^2\) when \(b=6\).
a2 = k / b3
72 = k / 33
49 = k / 27 ⇒ k = 49 / 27
When b = 6
a2 = 49 / (27*63 )
a2 = 49 / 5832
+4620 
