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Suppose that \(a^2\) varies inversely with \(b^3\). If \(a=7\)when \(b=3\), find the value of \(a^2\) when \(b=6\).

tertre  Mar 11, 2018
 #1
avatar+87333 
+1

a2  = k / b3

 

72  = k / 33

 

49  =  k / 27     ⇒  k   =  49 / 27

 

When b  = 6

 

a2  =  49 / (27*63 )

 

a2  =  49 / 5832

 

 

cool cool cool

CPhill  Mar 11, 2018

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