The solutions to
\(2x^2 - 10x + 13 = 0\)
are \(a+bi\) and \(a-bi\) where \(a\) and \(b\) are positive. What is \(a\cdot b\)?
The roots of 2x^ 2- 10x + 13 = 0 are (5 - i)/4 and (5 + i)/4, so ab = (5/4)(-1/4) = -5/16.
