Using row notation, solve:
10(e-4)=20(f-e)
20(f-4)=10(e+f)
Hi GR0001!
10(e - 4) = 20(f - e)
10e - 40 = 20f - 20e
e - 4 = 2f - 2e
3e = 2f + 4
20(f - 4)=10(e+f)
2(f - 4) = e + f
2f - 8 = e + f
f = e + 8
3e = 2(e + 8) + 4
e = 20
f = 20 + 8
f = 28.
So e = 20 and f = 28.
I hope this helped. :)))
=^._.^=
