Let \(b\) and \(c\) be constants such that the quadratic \(-2x^2+bx+c\) has roots \(3+\sqrt5\) and \(3-\sqrt5\). Find the vertex of the graph of the equation \(y=-2x^2+bx+c\)
please include thorough explanation
Nvm, i solved it. answer is (3,10)
+619 
