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I just finished geometry and im doing algebra II over the summer, so i am having trouble remembering algebra I stuff.  

How do you convert an equation from vertex form (I think its vertex form, correct me if im wrong: 2(x-3)^2+2) to standard form.  also, i cant remeber if i distibute the 2 before I square it or what. please help me

 Jun 11, 2020
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For an equation like:                        y  =  2(x - 3)2 + 2

you'll want to do the squaring first:  y  =  2[(x-3)(x-3)] + 2

                                                        y  =  2[x2 - 6x + 9] + 2

then, distribute:                               y  =  2x2 - 12x + 18 + 2

finally, simplify:                                y  =  2x2 - 12x + 20

 

If you distributed the 2 first, you would get the wrong answer because, when you squared, you would also

be squaring the 2 and you need to use the 2 only once.

 Jun 11, 2020

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