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Suppose we have a bag with 10 slips of paper in it. Eight of these have a 3 on them and the other two have a 9 on them.

a) What is the expected value of the number shown when we draw a single slip of paper?

b)What is the expected value of the number shown if we add one additional 9 to the bag?

 Mar 7, 2020
 #1
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a) The expected value is 24/10 = 12/5.

 

b) The expected value is 28/11.

 Mar 7, 2020
 #2
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I think the expected value would be    3 x 1/10   = .3      there are 8 of these   = .24

                                                            9 x 1/10  = .9        there are 2 of these = 1.8         sum = 4.2

  (8x 3 + 2 x 9 ) / 10 = 4.2

 

 

 

now add a '9' piece of paper        3 x 1/11 x 8 = 2.1818

                                                     9 x 1/11 x 3 = 2.4545                sum = 4.63

 

[(8x3)+(3x9)]/11 = 4.63

 Mar 7, 2020
edited by ElectricPavlov  Mar 7, 2020
 #3
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Those were correct! Thank you!

somehelpplease  Mar 8, 2020

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