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solve algebraically the simultaneous equation

x^2*y^2=25

y-2^x=5 

please explain the working outs to me as well

Guest Jun 15, 2017
 #1
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0

solve algebraically the simultaneous equation

x^2*y^2=25

y-2^x=5 

please explain the working outs to me as well

 

 

I know you asked to " solve algebraically", but I couldn't!!. So, I tried to solve them "heuristically", and I got these results:

x = -0.903404    and     y = 5.53462

x = 0.748498      and     y = 6.68004

Guest Jun 15, 2017

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