solve algebraically the simultaneous equation
x^2*y^2=25
y-2^x=5
please explain the working outs to me as well
solve algebraically the simultaneous equation
x^2*y^2=25
y-2^x=5
please explain the working outs to me as well
I know you asked to " solve algebraically", but I couldn't!!. So, I tried to solve them "heuristically", and I got these results:
x = -0.903404 and y = 5.53462
x = 0.748498 and y = 6.68004
