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What is the minimum possible value for y in the equation y=x^2+12x+5 ?

 Apr 4, 2020
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y=x^2+12x+5

 

Use -b/2a and x= -12/2(1)=-6.

 

Thus, y=(-6)^2+12(-6)+5=-31, and that is the minimum value for y.

 Apr 4, 2020

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