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Algebra problem

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Solve for y if 9^y = 3^5*9*6/(27*3).

Jun 15, 2022

#1
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Note that the right hand side is just a constant.

Take log on both sides:

$$\log_9 (9^y) = \log_9 \left(\dfrac{3^5 \cdot 9 \cdot 6}{27 \cdot 3}\right)\\ y = \log_9 \left(\dfrac{3^5 \cdot 9 \cdot 6}{27 \cdot 3}\right)$$

I will leave the simplification to you.

Jun 15, 2022