+0

# Algebra problem

0
76
1

Solve for y if 9^y = 3^5*9*6/(27*3).

Jun 15, 2022

### 1+0 Answers

#1
+9459
0

Note that the right hand side is just a constant.

Take log on both sides:

$$\log_9 (9^y) = \log_9 \left(\dfrac{3^5 \cdot 9 \cdot 6}{27 \cdot 3}\right)\\ y = \log_9 \left(\dfrac{3^5 \cdot 9 \cdot 6}{27 \cdot 3}\right)$$

I will leave the simplification to you.

Jun 15, 2022