Solve for y if 9^y = 3^5*9*27^3
Get the bases the same on each side
9^y = (3^5) * (9) * (27^3)
(3^2)^y = (3^5) * (3^2) * (3^3)^3
3^(2y) = (3^7) * ( 3^9)
3^(2y) = (3)^16 now...... solve for the exponents
2y = 16
y =16 / 2 = 8
