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Solve for y if 9^y = 3^5*9*27^3

 Jun 20, 2022
 #1
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Get the bases the same on  each side

 

9^y =  (3^5) * (9)  * (27^3)

 

(3^2)^y  =  (3^5) * (3^2) * (3^3)^3

 

3^(2y)  = (3^7) * ( 3^9)

 

3^(2y)  = (3)^16      now...... solve for  the exponents

 

2y = 16

 

y   =16  /  2   =    8

 

 

cool cool cool

 Jun 20, 2022

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