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Let \(0 \le a, b, c \le 5\) be integers. For how many ordered triples \((a,b,c)\) is \(a^2b+b^2c+c^2a-ab^2-bc^2-ca^2 = 0\)

 Sep 1, 2021
 #1
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There are 72 triples (a,b,c) that work.

 Sep 1, 2021

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