Algebra Question

Question

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Let $0 \le a, b, c \le 5$ be integers. For how many ordered triples $(a,b,c)$ is $a^2b+b^2c+c^2a-ab^2-bc^2-ca^2 = 0$

sherwyo Sep 1, 2021

Guest · Answer 1 · 2021-09-01T11:47:33

There are 72 triples (a,b,c) that work.