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If 3a + b + c = -3, a + 3b + c = 9, a + b + 3c = -19, then find abc.

 Nov 22, 2021
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Hello Guest,

 

If 3a + b + c = -3, a + 3b + c = 9, a + b + 3c = -19, then find abc.

 

\(3a+b+c=-3 \mbox { } (1)\)

\(a+3b+c=9 \mbox { } (2)\)

\(a+b+3c=-19 \mbox { } (3)\)

 

\((a, \mbox { } b, \mbox { } c) = (-\frac{1}{5}, \mbox { } \frac{29}{5}, \mbox { } -\frac{41}{5})\)

 

Now multiply them.

 

Hope that was helpful.^^

 

Straight

 Nov 22, 2021

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