+678 Hello Guest,
If 3a + b + c = -3, a + 3b + c = 9, a + b + 3c = -19, then find abc.
\(3a+b+c=-3 \mbox { } (1)\)
\(a+3b+c=9 \mbox { } (2)\)
\(a+b+3c=-19 \mbox { } (3)\)
\((a, \mbox { } b, \mbox { } c) = (-\frac{1}{5}, \mbox { } \frac{29}{5}, \mbox { } -\frac{41}{5})\)
Now multiply them.
Hope that was helpful.^^
Straight
