If x>2 then (x^2-x-6)/(x^2-4)=
Solve for x over the real numbers: (x-3)/(x-2) = 0 Multiply both sides by x-2: x-3 = 0 Add 3 to both sides: Answer: | | x = 3
\(\frac{x^2-x-6}{x^2-4}\\ =\frac{(x-3)(x+2)}{(x-2)(x+2)} \qquad x\ne-2\qquad \mbox{because it has to be greater than 2}\\ =\frac{x-3}{x-2} \)
