Adam is 3 times as old as Cynthia and Fred is 16 years younger than Adam. One year ago, Adam's age was twice the sum of Cynthia's & Fred's age. Find their present age
Adam is 3 times as old as Cynthia and Fred is 16 years younger than Adam. One year ago, Adam's age was twice the sum of Cynthia's & Fred's age. Find their present age.
Let Cynthia's age = C
Adam's age =3C
Fred's age =3C - 16
3C - 1 =2[C - 1 + 3C - 16 - 1], solve for C
C = 7 - Cynthia's age today.
7x3 = 21 - Adam's age today
21 - 16 = 5 - Fred's age today.
21 -1 =2[7-1 + 5 - 1]
20=2[6 + 4]=20 - Their ages 1 year ago.