**1.** Simplify.

^3√27x^6y^3

Assume all variables are nonnegative.

**2.** What is the expression in radical form?

(3x^2)^2/3

A. √9x^4

B. √3x^3

C. √3x^4

D. √27x^6

Guest Sep 17, 2017

#1**0 **

cube root of 27 is 3 cause 3^3=27

can not really simplify the others

3^2/3 is cube root of 9

(x^2)^2/3 is x^4/3 or cube root of x^4

so cube root of 9x^4, i assume A is correct but mistyped?

Guest Sep 17, 2017

#2**0 **

\(\sqrt[3]{27x^6y^3}\) can be simplified further.

Let's write all of the variables as numbers to the power of the 3.

\(\sqrt[3]{3^3\left(x^2\right)^3y^3}\)

To make this even easier, i'll distribute the cubed root to every term.

\(\sqrt[3]{3^3}*\sqrt{\left(x^2\right)^3}*\sqrt[3]{y^3}\)

Now, simplify.

\(3x^2y\)

TheXSquaredFactor
Sep 17, 2017