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# Algebra

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Find the sum of the cubes of the solutions of x^2-12x+4=0.

Sep 25, 2020

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Find the sum of the cubes of the solutions of x^2-12x+4=0.

Hello Guest!

$$x^2-12x+4=0$$

$$x=6\pm \sqrt{36-4}=6\pm \sqrt{2^5}$$

$$x_1=6+2^2\sqrt{2}\\ x_2=6-2^2\sqrt{2}$$

$$x_1^3+x_2^3=1584=2^4\cdot9\cdot 11$$

!

Sep 25, 2020
edited by asinus  Sep 25, 2020