One ordered pair (a,b) satisfies the two equations ab^4 = 384 and ab^5 = 4608. What is the value of a in this ordered pair?
\(ab^5=4608\) -----> 1
\(ab^4=384\) -------> 2
\(\frac{1}{2}\) Divide 1 by 2
\(b=\frac{4608}{384}\)
\(b=12\)
\(a\times (12)^4=384\)
\(a=\frac{1}{54}\)
