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The quadratic 2x^2 - 6x + 8 can be written in the form a(x + b)^2 + c, where a, b, c and are constants. What is a + b + c?

 Dec 12, 2020
 #1
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= 2 ( x^2-6x)       + 8

= 2 (x-3)2   - 18 + 8

= 2 (x-3)-10             take it from here................

 Dec 12, 2020
 #2
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**** edit ***

= 2 ( x^2-3x)       + 8

= 2 (x-1.5)2   -4.5 +  8

= 2 (x-1.5)2  + 3.5             take it from here................

Guest Dec 12, 2020

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