The quadratic 2x^2 - 6x + 8 can be written in the form a(x + b)^2 + c, where a, b, c and are constants. What is a + b + c?
= 2 ( x^2-6x) + 8
= 2 (x-3)2 - 18 + 8
= 2 (x-3)2 -10 take it from here................
**** edit ***
= 2 ( x^2-3x) + 8
= 2 (x-1.5)2 -4.5 + 8
= 2 (x-1.5)2 + 3.5 take it from here................
