When f(x) = ax^3 - 6x^2 + bx - 5 is divided by x - 1, the remainder is 5. When f(x) is divided by x - 2, the remainder is -53. Find the ordered pair (a,b).
Sub in x = 1
a - 6 + b -5 = 5
a+b - 16 = 0 (1)
sub in x = 2
8a - 24 + 2b -5 = -53
8a +2b +24 = 0 (2)
Two equations with two unknowns solve for a and b
mutilpy (1) by -8
-8a-8b+128 = 0 add to (2)
-6b +152 = 0
b = 25 1/3 a= - 9 1/3