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Write the equation of the line that it is perpendicular to 5x + 8y = 16 and passes through (-5,7)

 Sep 15, 2020
 #1
avatar+2452 
+3

Hi Guest!

 

Here is a hint for you. If two lines are perpendicular, the product of their slopes is -1. With this hint, try finding the slope of the other equation and plugging in x=-5 and y=7 to get the y intercept! :D

 

If this is still confusing, I can give you another hint or a full solution.

 Sep 15, 2020
 #2
avatar+132 
+1

5x+8y=16 --> 8y=-5x+16 --> y=-5/8x+2. To be perpendicular, slope has to be 8/5. So y=8/5x+b. We can plug in given coordinates to get 7=8/5*-5+b -->7=-8+b --> b=15. So eqn is y=8/5x+15 or in point-slope form, y=8/5x+15 --> 5y=8x+75 --> 5y-8x=75 

 Sep 15, 2020

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