+0

# Algebra

+1
153
3

1. Simplify

x^2+4x+3

--------------

2x-1

--------------

x^2+x

------------

2x^2-3x+1

2.

4(x+6)       (x+10)

---------  x  ----------

(x-2)          24(x+6)

thank you.

Apr 22, 2021

#1
+2

1. $$x^2+4x+3 = (x+1)(x+3)$$

2. Cannot be simplified further

3. $$x^2 + x = x(x+1)$$

4. $$2x^2-3x+1 = \left(2x-1\right)\left(x-1\right)$$

5. $$\frac{4\left(x+6\right)}{x-2}\cdot \frac{x+10}{24\left(x+6\right)} = \frac{x+10}{6\left(x-2\right)}$$

Hope this helped! AnxiousLlama

Apr 22, 2021
#2
+1

THX, AnxiousLlama  !!!

I think  that  the  first one  isn't  4  separate problems.....I  think  it's supposed to be

(x^2 + 4x + 3)   /   (2x - 1)

____________________

(x^2 + x)  / (2x^2 - 3x + 1)

This  can be expressed  as

(x^2 + 4x + 3)          (2x^2  - 3x  + 1)

___________   x    ______________                   factor  where possible

(2x - 1)                (   x^2  +  x )

(x + 3) ( x + 1)         (2x - 1) ( x  - 1)

___________   x     _____________                "cancelling"  we  get

2x - 1                       x ( x + 1)

(x +  3)  ( x - 1)            x^2  + 2x   - 3

_____________   =     ___________

x                              x   Apr 22, 2021
#3
+2

Oh! Sorry for the misunderstanding!

AnxiousLlama  Apr 22, 2021