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Find the vertex of the graph of the equation x - y^2 + 8y = 13 + 6y + y^2.

 Jul 31, 2021
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Need to 'massage' this around to vertex form of a parabola   ( a sideways parabola due to x = y^2 form)   x = a(y-k)^2 + h

x - y^2 + 8y = 13 + 6y + y^2

x = 2y^2 -2y    + 13        complete the square for 'y'

x = 2 ( y^2-1)   + 13

x = 2 ( y-1/2)^2   - 1/2 + 13

x = 2 (y-1/2)^2 + 12.5

 

           vertex is   (12.5 , .5)

 Jul 31, 2021

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