+613 Let x and y be nonnegative real numbers. If xy = \frac{2}{5}, then find the minimum value of 6x + \frac{3}{5y}.
+1950 First, let's isolate y in the first equation.
xy=2/5y=2/(5x)
Plugging this value into the second expression, we get
6x+3/(2/(5x))=6x+(15/2)x=(27/2)x
However, notice that there is no mimumum value or maximum value because the smaller x is, the smaller the number is to no limit.
There are absolutely no restrictions for this expression.
Thanks! :)
