+551 Let x and y be nonnegative real numbers. If xy = \frac{2}{5}, then find the minimum value of 6x + \frac{3}{5y}.
+1926 First, let's isolate y in the first equation.
\(xy = 2/5 \\ y = 2 / (5x) \)
Plugging this value into the second expression, we get
\(6x + 3 / (2 / (5x) ) = \\ 6x + (15/2)x = \\ (27/2) x\)
However, notice that there is no mimumum value or maximum value because the smaller x is, the smaller the number is to no limit.
There are absolutely no restrictions for this expression.
Thanks! :)
