Algebra

First, let's simplify all like terms and bring all terms to one side. 

We get the equation

\(2x^{2}+2x+7=0\)

 

Now, using the quadratic equation, we finally get two answers. We find that we have

\(x=-\frac{1}{2}+\sqrt{13}\cdot (\frac{1}{2}i)\\ x=-\frac{1}{2}-\sqrt{13}\cdot (\frac{1}{2}i)\)

 

Now we know what A and B are. We find that

\(a=-1/2; b = \frac{\sqrt{13}}{2}\)

 

Multiplying them toeghet, we finally come up with the answer. 

We finally have 

\(ab=-\frac{\sqrt{13}}{4}\)

 

Thus, our final answer is -sqrt(13)/4

 

Thanks! :)