One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
ab^4 = 48 (1)
ab^2 = 4 (2)
Divide (1) by (2)
b^2 = 12
b = +/- sqrt 12
Using (2)
a ( 12) = 4
a = 1/3
(a,b) = (1/3 , sqrt 12) , (1/3, -sqrt 12)
The solution is (a,b) = (2,8).
+1266 
