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algebra

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70
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I'm new to this site, and here is a question I am stuck on.

I am trying to multiply everyone out but I always can't seem to solve it. Any help would be appreciated!

Jan 16, 2021

#1
+168
+1

First, multiply the whole equation by $$(x-3)^2(x+5)$$:

$$1 = A(x-3)^2+B(x+5)(x-3)+C(x+5)\\$$

If we set x to be -5, we make B and C equal to zero, which we can use to solve for A:

$$1=A(-5-3)^2\\ 1=A(-8)^2\\ 1=64A\\ \boxed{A=\frac{1}{64}}$$

Jan 16, 2021