The quadratic 3x^2-24x+72 can be written in the form a(x+b)^2+c, where a, b, and c are constants. What is a+b+c?
3x^2-24x+72
3 ( x^2 - 8x) + 72 complete the square
3 ( x - 4)^2 -48 + 72
3 ( x-4)^2 + 24
You can finish !
The answer would then be \(3 + (-4) + 24\) which is 23.
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