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Find the area of the region enclosed by the graph of $x^2 + y^2 = 2x - 6y + 6 + 14x - 16y + 80$.

 Aug 10, 2024
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First, let's simplify the equation a bit. We get

x216x+y2+22y=86

 

Completing the square for BOTH x and y, we get the equation

x216x+64+y2+22y+121=86+64+121(x8)2+(y+11)2=271

 

This is a  circle centered at (8, - 11) with r^2  = 217

 

Now, we can find the area. We simply have

Area=pir2=271pi851.4

 

Thanks! :)

 Aug 10, 2024
edited by NotThatSmart  Aug 10, 2024

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