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Find the smallest value of x such that x^2 + 10x + 25 = 4.

 Jun 11, 2021
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=    x^2 + 10x+21 = 0    this is a bowl shaped parabola because the leading coefficient ( of x^2) is positive

                                         the minimum will occur at the value of    x = -b/2a  

                                                                                                       x  =  -10 / (2*1) = -5

     Use this value of x in the equation to calculate the minumum value of the equation.......

 Jun 11, 2021

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