Find all ordered pairs x, y of real numbers such that x+y=10 and x^3 + y^3 = 300 + x^2 + y^2. For example, to enter the solutions (2, 4) and (-3, 9), you would enter "(2,4),(-3,9)" (without the quotation marks).
x+y=10
x3+y3=300+x2+y2
x3+y3=(x+y)(x2−xy+y2)
10(x2−xy+y2)=300+x2+y2
9x2−10xy+9y2=300
9(x+y)2−28xy=300
28xy=600
xy=1507
x+y=10,xy=1507
I think you can solve on your own now. If you are having trouble, leave a note and ill do the rest.
+1556 
