Let f(x) = lfloor (2 - 3x)/(3x + 8) \rfloor Evaluate $f(1)+f(2) + f(3) + \dots + f(999)+f(1000).$ (This sum has $1000$ terms, one for the result when we input each integer from $1$ to $1000$ into $f$.)
https://web2.0calc.com/questions/floor-function_46
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