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What is the constant term of the expansion of (6x + 1/(3x))^8?

 May 12, 2021
 #1
avatar+128408 
+1

The  constant  term  will  be

 

C(8,4)  ( 6x)^4   ( 1/(3x))^4   =

 

70  *  ( 1296 x^4)  ( 1/ (81x^4)  =

 

1120

 

 

cool cool cool

 May 12, 2021
 #2
avatar+90 
+1

i think the   constant  term  will  be  C(8,4)  ( 6x)^4   ( 1/(3x))^4   = 70  ✕  ( 1296 x^4)  ( 1/ (81x^4)  =1120

 May 12, 2021

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