+0  
 
0
118
2
avatar

What is the constant term of the expansion of (6x + 1/(3x))^8?

 May 12, 2021
 #1
avatar+121056 
+1

The  constant  term  will  be

 

C(8,4)  ( 6x)^4   ( 1/(3x))^4   =

 

70  *  ( 1296 x^4)  ( 1/ (81x^4)  =

 

1120

 

 

cool cool cool

 May 12, 2021
 #2
avatar+93 
+1

i think the   constant  term  will  be  C(8,4)  ( 6x)^4   ( 1/(3x))^4   = 70  ✕  ( 1296 x^4)  ( 1/ (81x^4)  =1120

 May 12, 2021

14 Online Users

avatar