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Pearl writes down seven consecutive integers, and adds them up. The sum of the integers is equal to $214$ times the largest of the seven integers. What is the smallest integer that Pearl wrote down?

 Feb 6, 2024

Best Answer 

 #1
avatar+297 
+1

Alright, we set the largest of the 7 number to be x.

 

\(x-6+x-5+x-4+x-3+x-2+x-1+x = 214x\)

\(7x-21=214x\)

\(-21 = 207x\)

\(x = -21/207\)

that is not possible since they have to be integers.

hmmmm. Is this a trick question?

 Feb 6, 2024
 #1
avatar+297 
+1
Best Answer

Alright, we set the largest of the 7 number to be x.

 

\(x-6+x-5+x-4+x-3+x-2+x-1+x = 214x\)

\(7x-21=214x\)

\(-21 = 207x\)

\(x = -21/207\)

that is not possible since they have to be integers.

hmmmm. Is this a trick question?

Imcool Feb 6, 2024
 #2
avatar+297 
0

Ive googled this question. Electric Pavlov also answered this, and he got no answer as well. Check with your teacher, or the website, or whoever made this question.

 Feb 6, 2024

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