A triangle..ABC. Angle A is 10x-22 angle B is 4x angle C is 4x+10. The questions are looking for What X=, for what angle ABC=, for what angle ACB=, and for what angle CAB=.
The sum of the angles = 180°
So
10x -22 + 4x + 4x + 10 = 180 simplify
18x - 12 = 180
18x = 180 + 12
18x = 192
Angle ABC = 4 (32/3) = 128/3 ≈ 42.66°
Angle ACB = 4 (32/3) + 10 ≈ 52.66°
Angle CAB = 10 (32/3) -22 = 320/3 - 22 ≈ 84.66°
+4 
