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The roots of the quadratic equation z^2 + bz + c = 0 are -7 + 2i and 7 - 2i. What is b+c?

 Dec 5, 2021
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What is b+c?

 

Hello Guest!

 

\((z-(-7 + 2i)) * (z-(7 - 2i))=0\\ (z-(7-2i))(z+(7-2i))=0\\ z^2-(45-28i)=0\)

 

\(z^2 + bz + c = 0\)

\(b=0\\ c=-45+28i\\ \color{blue}b+c=-45+28i\)

laugh  !

 Dec 5, 2021

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