Algebra

Question

0

2

1

+773

Solve the inequality 4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1). Write your answer in interval notation.

bingboy Jan 18, 2025

+28

+1

Best Answer$4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1)$

When you combine like terms and simplify, you get $4t^2 \le -13t+35+4t^2-1$ which turns into $13t \le 34$

Divide both sides by 13: $t \le 34/13$

So the answer in interval notation is $(-\infty,34/13)$

Owinner Jan 19, 2025

Owinner · Answer 1 · 2025-01-19T01:27:51

$4t^2 \le -9t + 12 - 4t + 23 + (2t - 1)(2t + 1)$

When you combine like terms and simplify, you get $4t^2 \le -13t+35+4t^2-1$ which turns into $13t \le 34$

Divide both sides by 13: $t \le 34/13$

So the answer in interval notation is $(-\infty,34/13)$