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Algebra

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Rationalize the denominator: sqrt(3/5).

Sep 19, 2021

#1
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this should be correct if not just let me know. hope this helps.

$$\sqrt{\frac{3}{5}}=\frac{\sqrt{3}}{\sqrt{5}}$$

$$\frac{\sqrt{3}}{\sqrt{5}}=\frac{\sqrt{3}}{\sqrt{5}}*\frac{\sqrt{5}}{\sqrt{5}}$$

$$\frac{\sqrt{3}}{\sqrt{5}}*\frac{\sqrt{5}}{\sqrt{5}}=\frac{\sqrt{3*5}}{\sqrt{5*5}}$$

$$\frac{\sqrt{3*5}}{\sqrt{5*5}}=\frac{\sqrt{15}}{\sqrt{25}}$$

$$\frac{\sqrt{15}}{\sqrt{25}}=\frac{\sqrt{15}}{5}$$

Sep 19, 2021