Find the largest value of $x$ such that $3x^2 + 17x + 15 = 2x^2 + 21x + 12 - 5x^2 + 17x + 34.$
\(\text{By graphing this on Desmos, you get -1.119 or 4.619, and we choose the bigger one, or 4.619} \)
Rearrange as
6x^2 - 21x - 31 = 0
Using the Quad Formula, the largest x value is [ 21 + sqrt [ 21^2 + 24 *31] ] / 12 ≈ 4.619 { as 3.141 found !!! }
+617 
+42 
