For parts (a) through (d), let f(x) = 2x^2 - 13x + 20 - 5x^2 + 19x + 7.
What is the vertex of the parabola y = f(x)?
First, we can simplify f(x): \(f(x)=-3x^2+6x+27\). Then, we factor out -3 for \(f(x)=-3(x^2-2x-9)=-3(x-1)^2+30\).
From this equation, we get that the vertex of f(x) is (x, y) = (1, 30).