One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)
ab^4 = 48 divide the first wquation by the second
ab^2 = 4
b^2 = 12 take the both roots
b = ± sqrt (12) = ± 2sqrt (3)
ab^2 =4
a (12) = 4
a = 4/12 = 1/3
+636 
