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One ordered pair (a,b) satisfies the two equations ab^4 = 48 and ab^2 = 4. What is the value of b in this ordered pair? (Note: you may have to use the Tab key to get your cursor into the middle answer box.)

 Jun 2, 2024
 #1
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ab^4 = 48           divide  the first wquation by the second

ab^2 = 4

 

b^2 = 12          take the both roots

b =  ± sqrt (12) = ± 2sqrt (3)

 

ab^2 =4

a (12) = 4

a = 4/12 = 1/3

 

 

cool cool cool

 Jun 2, 2024

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